
Introducing Postgres Standard Deviation Function Better to just rule the values out when doing the queries, I feel. I’ve thought about manually going through and sanitising the data, but that’s like… manual labour, or something. So rather than the pay being listed as £20,000 to £25,000 (or whatever), they put in £200000-250000 or whatever, and it really skews everything big time.

The issue here is that I’m scraping data from numerous UK job sites, and some absolute chimps decide to enter their pay information in pennies rather than pounds. This data comes from my other site – one I often bang on about on here as a basis for my examples (and frustrations).

Here’s the problem, as I faced it (on the front end, at least): My knowledge tops out around GCSE-tier and I’m very grateful that computers are largely clever enough to do all the stuff I need with a little bit of Googling to help me out.īut nevertheless, this one stumped me for a while. OK, so cards on the table time, I am no maths whizz. What you need (probably) is Postgres’s standard deviation function.Īnd fortunately for you (and me), it’s much easier to implement than you might be thinking. What you’d like to do is eliminate the outlying values from your result set, and keep the ones nearer the “normal” values. Your numbers look alright, but some very high (or very low) values seem to be throwing things out of whack. Both are samples, why do we n-1 during t test, but not z test? I get that samples need to -1 to compensate for accuracy, but why didn't we do it for z tests?ĭon't feel pressure to answer all the questions, just what you can, perhaps the collective can help me out of this rut.Here’s the problem we are addressing today: you have a set of numerical data returned by your Postgres query.Is the sample proportion confidence interval of a single sample VS sample mean which is the average of multiple samples?.What is the difference between sample proportion and sample mean? Is the former Bernuli distribution and another not?.sample proportion, we take $\hat)$ while the other uses S (sample standard deviation)?.

Hope to find some help out here.īoth are samples, but why when looking for confidence interval of a: Sorry, I'm just on Khan academy and can't seem to grasp the essence of statistics.
